Korrigiere Separator in Join-Methode und benenne Klasse um

DigitalData.Core.Application/EnumerableExtensoins.cs

@@ -0,0 +1,23 @@
+using System;
+using System.Collections.Generic;
+using System.Linq;
+using System.Text;
+using System.Threading.Tasks;
+
+namespace DigitalData.Core.Application
+{
+    /// <summary>
+    /// Provides extension methods for IEnumerable<T>.
+    /// </summary>
+    public static class EnumerableExtensions
+    {
+        /// <summary>
+        /// Concatenates the members of a collection, using the specified separator between each member.
+        /// </summary>
+        /// <typeparam name="T">The type of the elements of the enumerable.</typeparam>
+        /// <param name="enumerable">The IEnumerable<T> whose elements to concatenate.</param>
+        /// <param name="separator">The string to use as a separator. Separator is included in the returned string only between elements of the collection.</param>
+        /// <returns>A string that consists of the elements in the collection delimited by the separator string. If the collection is empty, the method returns String.Empty.</returns>
+        public static string Join<T>(this IEnumerable<T> enumerable, string separator = ". ") => string.Join(separator, enumerable);
+    }
+}