Common: Improve BaseForms and ErrorHandler

This commit is contained in:
Jonathan Jenne
2021-04-26 16:31:41 +02:00
parent 72e639dc0c
commit 18786bee33
4 changed files with 77 additions and 12 deletions

View File

@@ -14,9 +14,14 @@ Namespace Base
_Form = Form
End Sub
Public Sub ShowErrorMessage(Exception As Exception)
Public Sub ShowErrorMessage(Exception As Exception, Origin As String)
Dim oMessage = GetMessage(Exception, Origin)
ShowErrorMessage(Exception, Origin, oMessage)
End Sub
Public Sub ShowErrorMessage(Exception As Exception, Origin As String, Message As String)
_Logger.Error(Exception)
MessageBox.Show(GetMessage(Exception), _Form.Text, MessageBoxButtons.OK, MessageBoxIcon.Exclamation)
MessageBox.Show(Message, _Form.Text, MessageBoxButtons.OK, MessageBoxIcon.Error)
End Sub
Public Sub ShowInfoMessage(Text As String)
@@ -24,8 +29,7 @@ Namespace Base
MessageBox.Show(Text, _Form.Text, MessageBoxButtons.OK, MessageBoxIcon.Information)
End Sub
Private Function GetMessage(Exception As Exception) As String
Dim oCallingClass = LogConfig.GetClassFullName(IncludeMethodNames:=True, Parts:=2)
Private Function GetMessage(Exception As Exception, Origin As String) As String
Dim oMessage As String = String.Empty
If TypeOf Exception Is SqlClient.SqlException Then
@@ -37,13 +41,13 @@ Namespace Base
ElseIf TypeOf Exception Is NoNullAllowedException Then
oMessage = "Einige benötigte Felder wurde nicht ausgefüllt."
Else
oMessage = $"Es ist ein unerwarteter Fehler in {oCallingClass} aufgetreten. Mehr Informationen finden Sie im Log."
oMessage = $"An unhandled exception occurred in {Origin}: " & vbNewLine &
Exception.Message & vbNewLine & vbNewLine &
"More information can be found in the Application Log."
End If
If _LogConfig.Debug Then
oMessage &= vbNewLine & vbNewLine & "== Debug Informationen =="
oMessage &= vbNewLine & vbNewLine & "Die ursprüngliche Fehlermeldung lautet:"
oMessage &= vbNewLine & Exception.Message
oMessage &= vbNewLine & vbNewLine & "=== Debug Information ==="
oMessage &= vbNewLine & vbNewLine & "Stacktrace:"
oMessage &= vbNewLine & Exception.StackTrace
End If