49 lines
1.9 KiB
VB.net

Imports DigitalData.Modules.Base
Public NotInheritable Class frmAbout
Private Sub AboutBox1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
' Legen Sie den Titel des Formulars fest.
Dim ApplicationTitle As String
If My.Application.Info.Title <> "" Then
ApplicationTitle = My.Application.Info.Title
Else
ApplicationTitle = System.IO.Path.GetFileNameWithoutExtension(My.Application.Info.AssemblyName)
End If
If USER_LANGUAGE = "de-DE" Then
Me.Text = String.Format("Information zu: {0}", ApplicationTitle)
Else
Me.Text = String.Format("Information about: {0}", ApplicationTitle)
End If
lblProduktname.Text = My.Application.Info.ProductName
lblVersion.Text = String.Format("Version {0}", My.Application.Info.Version.ToString)
lblCompanyName.Text = My.Application.Info.CompanyName
txtDescription.Text = My.Application.Info.Description
End Sub
Private Sub OKButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OKButton.Click
Me.Close()
End Sub
Private Sub LinkLabel_SupportPortal_LinkClicked(sender As Object, e As LinkLabelLinkClickedEventArgs) Handles LinkLabel_SupportPortal.LinkClicked
Try
Me.LinkLabel_SupportPortal.LinkVisited = True
Dim oSql As String = "SELECT CAT_STRING FROM TBDD_CATALOG WHERE CAT_TITLE = 'DDSUPPORT_PORTAL'"
Dim oSupportLink As String = DATABASE_ECM.GetScalarValue(oSql)?.ToString()
If Not String.IsNullOrEmpty(oSupportLink) Then
Process.Start(oSupportLink)
Else
MsgBox("Support-Link nicht gefunden.", MsgBoxStyle.Information)
End If
Catch ex As Exception
MsgBox("Fehler beim Öffnen des Support-Links: " & ex.Message, MsgBoxStyle.Critical)
End Try
End Sub
End Class