10.01.2024

This commit is contained in:
Jonathan Jenne
2024-01-10 09:31:04 +01:00
parent b7fbb21076
commit 277f5d3f0d
8 changed files with 148 additions and 27 deletions

View File

@@ -12,8 +12,8 @@ Public Class EmailModel
Public Function Insert(pEmail As EmailData) As Boolean
Try
Dim oSql = "INSERT INTO [dbo].[TBEMLP_EMAIL_OUT] "
oSql += " (EMAIL_ADRESS, EMAIL_SUBJ, EMAIL_BODY, ADDED_WHO, SENDING_PROFILE, REFERENCE_ID, REFERENCE_STRING, REMINDER_TYPE_ID, WF_ID) "
oSql += " VALUES (@EMAIL_ADRESS, @EMAIL_SUBJ, @EMAIL_BODY, @ADDED_WHO, @SENDING_PROFILE, @REFERENCE_ID, @REFERENCE_STRING, @REMINDER_TYPE_ID, @WF_ID)"
oSql += " (EMAIL_ADRESS, EMAIL_SUBJ, EMAIL_BODY, ADDED_WHO, SENDING_PROFILE, REFERENCE_ID, REFERENCE_STRING, REMINDER_TYPE_ID, EMAIL_ATTMT1, WF_ID) "
oSql += " VALUES (@EMAIL_ADRESS, @EMAIL_SUBJ, @EMAIL_BODY, @ADDED_WHO, @SENDING_PROFILE, @REFERENCE_ID, @REFERENCE_STRING, @REMINDER_TYPE_ID, @EMAIL_ATTMT1, @WF_ID)"
Dim oCommand As New SqlCommand(oSql)
oCommand.Parameters.Add("EMAIL_ADRESS", SqlDbType.NVarChar).Value = pEmail.EmailAdress
oCommand.Parameters.Add("EMAIL_SUBJ", SqlDbType.NVarChar).Value = pEmail.EmailSubject
@@ -23,6 +23,7 @@ Public Class EmailModel
oCommand.Parameters.Add("REFERENCE_ID", SqlDbType.Int).Value = pEmail.ReferenceID
oCommand.Parameters.Add("REFERENCE_STRING", SqlDbType.NVarChar).Value = pEmail.ReferenceString
oCommand.Parameters.Add("REMINDER_TYPE_ID", SqlDbType.Int).Value = 202377
oCommand.Parameters.Add("EMAIL_ATTMT1", SqlDbType.NVarChar).Value = pEmail.EmailAttachment
oCommand.Parameters.Add("WF_ID", SqlDbType.Int).Value = pEmail.EmailType ' Wegen DB-Trigger MUSS dieser Wert gesetzt werden
If Database.ExecuteNonQuery(oCommand) Then